Hess’s Law

Enthalpy and Hesss Law Lab Introduction Every chemical answer is go with by a change in inflame. Thermochemical answers include the enkindle of reaction as part of the comparability. The warming released or absent-minded in a reaction at constant pressure is the Enthalpy change (? Hrxn) for the reaction. The henry change for each reaction is unique to that reaction. Many harbors for ? Hrxn were by experimentation determined, and many were calculated used Hesss law.This lab leave behind deck the principle of Hesss law if a reaction can be carried out in a series of looks, the sum of the enthalpies for each step matess the enthalpy change for the over all in all reaction. ?Hrxn = ? Hstep1 + ? Hstep2 . The three reactions that we allow for be victimisation are as follows response 1 reply 2 Reaction 3 NaOH(s) + HCl(aq) ? NaCl(aq) + H2O(l) NaOH(aq) + HCl(aq) ? NaCl(aq) + H2O(l) NaOH(s) ? NaOH(aq) Since reaction 1 can be obtained by adding reactions 2 and 3, the ? Hrxn1 should equal ? Hrxn2 + ? Hrxn3. At constant pressure ? Hrxn = qp. We cannot directly measure ?Hrxn or qp, but we can measure the change in temperature for a response, and victimization the precise warming of the root, and the grams of answer, we can find qp using the following equation Equation 1 q = (grams of solution) x ( special(prenominal) oestrus of solution) x ? T The lovingness that is released by the reaction will be absorbed by 2 the surroundings in this case, the weewee in the solution and the calorimeter itself Equation 2 qrxn = -(qsolution + qcalorimeter) Since every groups calorimeter is slightly different, the heat competency for the calorimeter will need to experimentally determine before it is used.Pre-Lab Questions 1. 2. 3. 4. 5. Define ? Hrxn. Define specific heat, and heat capacity. How are these two terms different? The specific heat of a solution is 4. 18 J/gK and its density is 1. 02g/mL. The solution is make by combining 25. 0mL of solution A with 2 5. 0mL of solution B, with each solution initially at 21. 4C. The final temperature of the combined solutions is 25. 3C. take the heat of reaction, qrxn, presume no heat loss to the calorimeter. If the calorimeter in the reaction above has a Heat Capacity of 8. 20J/C, recalculate the qrxn, taking the heat loss to the calorimeter into account.If the reaction above between solutions A and B goes as follows A(aq) + B(aq) ? AB(aq), and the molarity of A in solution A is 0. 60M, and the molarity of B in solution B is 0. 60M, what is the enthalpy of reaction (? Hrxn), for the formation of 1 mole of AB in solution. Express ? Hrxn in kJ/mol Materials NaOH(s) HCl(aq, 1. 0M) 250mL Beaker Digital Thermometer Graduated cylinder Balance Distilled Water NaOH(aq, 1. 0M) Calorimeter w/ Lid Magnetic rivalrer and Stir Bar Procedure Part 1 Determining the heat capacity of the Calorimeter 1. 2. 3. 4. 5. 6. 7. 8.Set up a calorimeter of two nested cups with a cover inside a beaker. Measure 50. 0mL of room temp distilled piddle into the calorimeter. Place the calorimeter on a magnetic disposerer and add a hasten bar, set the stir bar to stir slowly. (Alternatively, gently stir the solution with the thermometer. ) spirit the Temperature of the water in the calorimeter. Heat or obtain roughly 75mL of 70? C water. Measure out 50. 0mL of this water using a graduated cylinder. Record the temperature of the hot water, and pour the hot water into the room temp water in the calorimeter. Cover the calorimeter and insert the thermometer. . Stir and inscribe the temperature every 20 seconds for three minutes. 10. Empty and prohibitionist the inside of the calorimeter, thermometer, and stir bar. Part 2 Determining the heats of Reaction Reaction 1 NaOH(s) ? NaOH(aq) 1. Weigh out slightly 2. 0g of NaOH(s). Record the actual weight. 2. Add 100. 0mL of room temperature water to the calorimeter. 3. Start the stir bar and record the temperature of the water. 4. Add the NaOH(s), and record the temperature at one conviction every 20 seconds, until it boodle changing. 5. Dump out the NaOH(aq) into the sink, rinse out, and dry the calorimeter, thermometer, and stir bar.Reaction 2 NaOH(aq) + HCl(aq) ? NaCl(aq) + H2O(l) 6. Combine 50. 0mL of 1. 0M NaOH and 50. 0mL 1. 0M HCl, in the calorimeter, 7. Record the temperature once every 20 seconds, until it stops changing. 8. Dump out the solution into the sink, rinse and dry the calorimeter, thermometer, and stir bar. Reaction 3 NaOH(s) + HCl(aq) ? NaCl(aq) + H2O(l) 9. Measure 50. 0mL of Distilled water into the calorimeter. 10. Add 2. 0g of NaOH(s) (Record the actual weight) and 50. 0mL of 1. 0M HCl to your calorimeter 11. Record the temperature once every 20 seconds, until it stops changing.. 12.Dump out the solution into the sink, rinse and dry the calorimeter, thermometer, and stir bar. Data Create a entropy table to clench all of your data for the 2 parts. Make sure you have a space for the initial and final temperatu res, as well as the fix or volume for each reactant. Calculations 1. Calculate the Heat Capacity of the Calorimeter. a. When equal volumes of hot and cold water are combined, if there is no heat loss the new temperature should be the fair of the two starting temperatures. In actual practice, the new temperature will be slightly less than the average because of heat lost to the calorimeter assembly.Additionally, when two solutions are mixed the thermometer cannot instantaneously record the temperature of the combined solutions. The solutions require some time to become completely mixed, and the thermometer ask time to come to temperature equilibrium with the solution. The theoretical temperature that the mixture would have if the serve occurred instantaneously can be found from a graph. Plot the data with temperature on the vertical axis versus time on the horizontal axis. The offshoot few points may be erratic because of incomplete mixing and insufficiency of temperature equil ibrium with the thermometer.The points that follow should occur in a straight pull out as the temperature slowly drops while heat is lost to the calorimeter and to the surroundings. Draw a straight row through these points, and extend it back to find the temperature at time zero, the theoretical instantaneous temperature of mixing, Tmix. See Figure 1. b. Calculate the average temperature of the hot and cold water, Tavg. c. The difference between the average temperature, Tavg and the instantaneous temperature, Tmix, is payable to the fact that some heat was lost by the water and absorbed by the calorimeter.Calculate q water, the heat lost by the water qwater = (grams of water) x (specific heat of water) x (Tmix Tavg) where qwater = heat lost by water and the specific heat of water is 4. 18 J/(gC). The heat absorbed by the calorimeter, qcalorimeter, will be equal to that lost by the water but face-to-face in sign. qcalorimeter = ? qwater d. Calculate the heat capacity of the calo rimeter, Ccalorimeter, which is the heat that the calorimeter absorbs each time the temperature of the solution changes 1C Ccalorimeter =qwater / (Tmix -Tinitial) where Tinitial is the initial temperature of the cool water. . Calculate ? H for Each Reaction. e. Graph the temperature versus time for each of the three reactions tested. Extrapolate the line back to find the theoretical instantaneous mixing temperature, Tmix, as you did above. f. Calculate the amount of heat evolved in each reaction, qrxn, by assuming that all of the heat is absorbed by the solutions and the calorimeter qrxn = heat absorbed by solution + heat absorbed by calorimeter qrxn = (grams of solution x specific heat of solution x ? Tsolution ) + (Ccalorimeter x ? Tsolution) where ? Tsolution = (Tmix Tinitial) for each reaction mixture.Assume that the density of the solutions is 1. 03 g/mL, and that the specific heat of the solutions is the same as that of water, 4. 18 J/(gC). g. 3. Calculate the note value o f the enthalpy change, ? H, in terms of kJ/mole for each of the reactions. Verify Hesss Law. . h. i. j. sermon Conclusion Write net ionic equations for the three reactions involved. Show how you essential arrange the first two equations to algebraically find the third. Calculate the value of ? H for the third reaction from your ? H values for the first two reactions using Hesss law. Find the percent difference between the calculated and measured values.